35p^2+165p-50=0

Solution for 35p^2+165p-50=0 equation:

35p^2+165p-50=0

a = 35; b = 165; c = -50;
Δ = b2-4ac
Δ = 1652-4·35·(-50)
Δ = 34225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34225}=185$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(165)-185}{2*35}=\frac{-350}{70}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(165)+185}{2*35}=\frac{20}{70}
=2/7
$